What is the total power the beam dump has to absorb? - proton beam vs prostatectomy
Completely naked all the electrons (away) 16O ions in an accelerator with a total voltage of 1.00 V ‡ accelerated 109 16O has 8 protons and 8 neutrons. The accelerator produces a beam of 6.37 · 1012 of these ions per second. This ion beam is completely stopped in a beam dump. What is absorbing the total power beam shot?
Wednesday, February 3, 2010
Proton Beam Vs Prostatectomy What Is The Total Power The Beam Dump Has To Absorb?
1 comment:
The potential energy is V * q = \\ u0026lt; 1.0x10 ^ 9V * 8 * 1.60x10 ^ 19 = 1.28x10 ^ C-9J (per ion)
Thus, energy Toal = 6.37x10 ^ 12 * 1.28x10 ^ -9 = 8154J / s =
This means that the beam dump must have a capacity of 8154J / s = 8154W
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